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prove the foll identity. (with solution)

cscx-cotx cosx = sinx

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Raela18viz
cscx-cotxcosx = sinx
(1/sinx) - [(cosxcosx)/sinx] = sinx
[(1-cos²x)/sinx] = sinx
[(cos²x - cos²x + sin²x)/sinx] = sinx
(1-cos²x)/sinx = sinx
(cos²x-cos²x+sin²x)/sinx = sin x
sin²x/sinx = sinx
sinx = sinx :)




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