Sagot :
[tex](x+2)^{2} = 3(x+2)[/tex]
[tex] x^{2} +4x+4 = 3x+6[/tex]
[tex] x^{2} +4x-3x+4-6=0[/tex]
[tex] x^{2} +x-2=0[/tex]
Final Answer: [tex] x^{2} +x-2=0[/tex]
Sorry for the late answer... :)
[tex] x^{2} +4x+4 = 3x+6[/tex]
[tex] x^{2} +4x-3x+4-6=0[/tex]
[tex] x^{2} +x-2=0[/tex]
Final Answer: [tex] x^{2} +x-2=0[/tex]
Sorry for the late answer... :)