1.
t=1.5\:\rm st=1.5s
v_i=0\:\rm m/sv
i
=0m/s
v_f=14.7\:\rm m/sv
f
=14.7m/s
The average acceleration of the golf ball
a=\frac{v_f-v_i}{t}=\frac{14.7-0}{1.5}=9.8\:\rm m/s^2a=
t
v
−v
=
1.5
14.7−0
=9.8m/s
2
2.hence,it takes 5.4 8 to bring the bicycle to a complete stop.(solution ito Rin)
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