Franceslowisaviz
Franceslowisaviz
Math
Answered
[tex] (\frac{3}{5}) ^{x^{2} -7x-8} [/tex]
Sagot :
AnneCviz
AnneCviz
[tex] (\frac{3}{5}) ^{x^{2} -7x-8} [/tex] = 1
May be written as
log(3/5) 1 = x² - 7x -8
But log(3/5) 1 = 0 ; so x² - 7x -8 = 0
x² - 7x -8 = 0
(x-8)(x+1) = 0
Therefore,
x = 8 ; x = -1
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