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the sum of three number is 90. find the numbers if the second number is 2 more tha twice the first and the third is two less than the sum of the first two

Sagot :

Peachocoviz
a+b+c=90
b=2a+2
c=(a+b)-2

c=(a+b)-2
c=a+2a+2-2
c=3a

a+b+c=90
a+2a+2+3a=90
6a=88
[tex] \frac{6a}{6} = \frac{88}{6} [/tex]
a=[tex] \frac{44}{3} [/tex]

b=2a+2
b=2([tex] \frac{44}{3} [/tex])+2
b=[tex] \frac{88}{3}+2 [/tex]
b=[tex] \frac{94}{3} [/tex]

c=(a+b)-2
c=([tex] \frac{44}{3} + \frac{94}{3} -2[/tex]
c=44

a+b+c=90
[tex] \frac{44}{3} + \frac{94}{3} +44=90[/tex]
46+44=90
90=90