Donnabelleviz
Answered

Find three consecutive even integers whose sum is 648

Sagot :

Manelviz
 Let..
 2x= first integer
 (2x+2) = second integer
(2x+4) = third integer

Solution:
 2x+(2x+2)+(2x+4) = 648
 6x = 648-6
 6x= 642
 x = 107
2x= 214
(2x+2) = 216
(2x+4) = 218

Therefore, the integers are 214, 216, and 218.