Answered

logx^2 -log2x/5 = 7.58

Sagot :

[tex]Logx^2 -log\frac{2x}{5} = 7.58[/tex]
[tex]Log\frac{x^2}{x} + log\frac{5}{2} = 7.58[/tex]
[tex]e^{(lnx)} = e^{(7.58-ln\frac{5}{2})} [/tex]
[tex]x = 783.45[/tex]