Answer:
A. 4
Step-by-step explanation:
[tex] \\ \tt{} {x}^{2} - 8x + 15 = 0[/tex]
[tex]\\ \tt{}a = 1\: \: \: \: \: b = - 8 \: \: \: \: \: c = 15[/tex]
[tex]\\ \tt{} = {b}^{2} - 4 ac[/tex]
[tex]\\ \tt{} = ( - 8 ){}^{2} - 4(1)(15)[/tex]
[tex]\\ \tt{} = 64 - 60[/tex]
[tex]\\ \huge \boxed{ \tt{} = 4} \\ \\ \\ \\ [/tex]
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