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what are the factors of 9 x²- 25​

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Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=3xa=3x and b=5b=5.

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=3xa=3x and b=5b=5.(3x+5)(3x−5)

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Answer:

[tex]a^{2}[/tex]- [tex]b^{2}[/tex] [tex]= ( a + b ) ( a - b )[/tex]

[tex]9 x 2 -25=(3x)2-(5) 2[/tex]

[tex](3x) 2 -(5)2=(3x+5)(3x-5)[/tex]

are the factors of 9 x²- 25​

Step-by-step explanation:

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