The equation of parabola is y^2-2x+6y+3=0
Obviously, it is a parabola Vertex at (h,k)
The Standard form of a parabola vertex at (h,k) opening to the right is (y-k)^2=4a(x-h)
y^2-2x+6y+3=0
y^2+6y=2x-3 Completing the square
y^2+6y+9=2x-3+9
(y+3)^2=2(x+3) or
[y-(-3)]^2=2[x-(-3)]
So, (h,k) is (-3,-3).
THe answer is Letter D.
