Let 'x' be the number on the tens place
'y' be the number on the units place
'x(10)+y' be the number
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From the statement 'the sum of a two-digit number is 12'
x + y = 12 ----equation 1
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From the statement 'the value of the number is two more than 11 times the tens digit'
x(10) + y = 11x + 2
10x + y = 11x + 2
11x - 10x = y - 2
x = y -2 -----equation 2
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Substitute equation 2 to equation 1
x + y = 12
y - 2 + y = 12
y+ y = 12 + 2
2y = 14
y = 7
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Substitute y=7 to equation 1
x + y = 12
x + 7 = 12
x = 12 - 7
x = 5
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The number as stated above is x(10) + y
10x + y = 10(5) + 7
= 50 + 7
= 57
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Therefore the number is 57.
