[tex]1)\\\\ \frac{(-2a^2+12a-18)\cdot (-1)}{(9-a^2)\cdot (-1)} = \frac{ 2a^2-12a+18 }{ a^2-9 } =\frac{ 2(a^2-6a+9) }{ (a-3) (a+3) } =\frac{ 2(a-3)^2 }{ (a-3) (a+3) }= \frac{ 2(a-3) }{ a+3 }[/tex]
[tex]2)\\\\ \frac{ -4a+8a-4 }{2a^2-2 } = \frac{ 4a-4 }{2(a^2-1) } = \frac{ 4(a-1) }{2(a -1)(a+1) } = \frac{ 2 }{ a+1 }[/tex]
