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The point (x,1) is 2√5 units from (2,3). Find x

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Shinalcantaraviz
use the distance formula, and you'll have:
[tex]d^2 = {(x_2-x_1)^2 + (y_2-y_1)^2} [/tex]
(2√5)² = (2-x)² + (3-1)²
20 = 4 - 4x + x² + 4
x² - 4x + 8 - 20 = 0
x² - 4x - 12 = 0 
(x-6)(x+2) = 0
x = 6, x=-2

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