Sagot :
the length of the sides of a triangle are: y, y+1 & 7cm
so
y+( y+1 )+7 = 56
2y + 1+7 =56
2y +8 =56
y = 48/2 = 24cm
the length of the sides of the triangle are: 24,25 & 7
so
y+( y+1 )+7 = 56
2y + 1+7 =56
2y +8 =56
y = 48/2 = 24cm
the length of the sides of the triangle are: 24,25 & 7
perimeter of atriangle=sum of 3 sides iey+y+1+7 =56 ie 2y+8=56 2y=56-8=48 2y=48 ie y=48/2=24