MinasakaRenviz
Answered

The sum of three consecutive multiples of 7 is equal to 252. Find the highest number.

Sagot :

MagorCSviz
7α + 7(α+1) + 7(α+2) = 252
7a + 7a + 7 + 7a + 14 = 252
21a + 21 = 252
21a = 252 -21
21a = 231
a = 11

77+84+91=252

91 is highest :)


Frongsviz
7(x+1)+7(x+2)+7(x+3)=252
7x+7+7x+14+7x+21=252
21x+42=252
21x=210
x=10
Substitute x=10 into 7(x+3)
7(10+3)=7(13)= 91

The answer is 91.