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A pedicab accelerates from rest at a constant rate of 2m/s². How fast will the pedicab be going at the end of 6s? How far has the pedicab traveled during this time?

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Rhyckayenviz
Equation:" V2=V1 +at "... Where V2= final velocity; V1= initial velocity (0); a= acceleration ( 2m/s^2); t=time (6 seconds)....substitute and solve: V2= 0 + (6*2) = 12 m/s--- answer. Next, find distance : d= (1/2 )at^2... d= (1/2)*2*6^2.... d= (1/2)*2*36= (1/2)* 72 = 36 meters..---answer

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