[tex]\frac{6}{x} +\frac{x-3}{4} = 2 \\ \\x\neq 0 \\\\\frac{6}{x} +\frac{x-3}{4 } -2=0\\\\\frac{24+x(x-3)-8x}{4x} =0 \\\\24+x(x-3)-8x =0[/tex]
[tex]24+x^2-3x-8x =0 \\ \\ x^2-11x+24 =0 \\ \\(x-3)(x-8)=0 \\ \\x-3 =0 \ \ \ or \ \ \ x-8 = 0 \\\\x=3 \ \ \ or \ \ \ x=8[/tex]
