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Solve the equation to find the roots of the given equation3x2 - 2x - 1 = 0

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Raquelviz
3x^2-2x-1=0

a=3
b=-2
c=-1

-b+-sqrt of b^2-4ac
            2a
-(-2)+- sqrt of (-2)^2-4(3)(-1)
               2(3)
2+-sqrt of 4+12
        6
2+-sqrt of 16
       6
2+-4
   6
2+4      2-4
 6           6
6            -2
6             6

x1=  1
x2=  -1
         3
hope it will help ^_^

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