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The__horizontal range covered by a projectile is at 45°angle of projection

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Zack1237viz

|✏️ANSWER ✏️|

The maximum horizontal range covered by a projectile is at 45°angle of projection

Step-by-step explanation:

Range of projectile, R

For θ = 45°, sin 2θ = sin 90° = 1 (maximum). In the nutshell, the range,R, increases with increasing angle of projection for 0° ≤ θ < 45°; the range,R, is maximum when θ = 45°; the range,R, decreases with increasing angle of projection for 45° < θ ≤ 90°

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