3. Two towers that are 45 miles apart track a satellite in orbit. The first tower's signal makes a 75° angle between the ground and satellite. The second tower forms 86° angle. a. How far is the satellite from each tower? b. How could you determine how far is the satellite above the earth? What is the altitude of the satellite?

Ano po answer po nyan...need ko po answer para sa math ko po

[tex]\tt a. \: \frac{b}{c} = \frac{ \sin(B) }{ \sin(C) } \\ \\ \tt C = 180° - 75° - 86° = 19° \\ \tt b = \purple{137.88 \: \: miles} \\ \\ \tt \frac{a}{c } = \frac{ \sin(A) }{ \sin(C) } ⇒ a = \purple{133.51 \: \: miles}[/tex]

Therefore, 137.88 miles from the first tower, 133.51 miles from the second tower.

[tex] \\ [/tex]

[tex] \tt b. \: A = \frac{1}{2} ab \sin(c) = \frac{1}{2} \times 133.51 \times 137.88 \\ \tt \times \sin(19°) = 2996.66 [/tex]

(Draw the dotted line CD [tex]\perp[/tex] AB)

[tex]\tt A = \frac{1}{2} \times AB \times CD = 2996.66 \\ \\ \tt CD = \purple{133.18 \: \: miles}[/tex]

Therefore, altitude of the satellite is 133.18 miles