A 1.25 kg ball is projected vertically upward from the ground with an initial speed of 5.6 m/s. (a) How high will it rise? (b) What is its speed when it is at half of its maximum height? Use conservation of mechanical energy to solve this problem. Kindly answer this seriously! Needed!
Yeah, correct. And velocity is given 5.6 minutes per second. So H will be equal to MGH 1 to 5 to 110 into velocity 5.6. So it will be equal to 1.3 Standing at one Point Please.
