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Answered

What is the standard form of 4x²-y²+2y-5=0 in hyperbola equation

Sagot :

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Answer:

x² - (y-1)²/4 = 1

Step-by-step explanation:

4x²-y²+2y-5 = 0

4x²-y²+2y = 5

4(x²) + -1(y²-2y) = 5

4(x²) + -1(y²-2y+1) = 5+(-1)

4(x²) - (y²-2y+1) = 5 - 1

4(x²) - (y+1)² = 4

Divide both sides by 4

4(x²)/4 - (y-1)²/4 = 4/4

x² - (y-1)²/4 = 1

Panda202125viz

QUESTION:

What is the standard form of 4x²-y²+2y-5=0 in hyperbola equation

ANSWER:

  • x² - (y-1)²/4 = 1

Step-by-step explanation:

4x²-y²+2y-5 = 0

4x²-y²+2y = 5

4(x²) + -1(y²-2y) = 5

4(x²) + -1(y²-2y+1) = 5+(-1)

4(x²) - (y²-2y+1) = 5 - 1

4(x²) - (y+1)² = 4

Divide both sides by 4

4(x²)/4 - (y-1)²/4 = 4/4

Therefore the answer is x² - (y-1)²/4 = 1

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