Answered

cube root of 16x plus cube root of 2x plus power of cube root of 54x

Sagot :

Daedalusviz
[tex] \sqrt[3]{16x} + \sqrt[3]{2x} + \sqrt[3]{54x} = \sqrt[3]{2^{3}*2x} + \sqrt[3]{2x} + \sqrt[3]{3^{3}*2x} [/tex]

we can bring now bring out numbers from the radical sign

[tex] 2\sqrt[3]{2x} + \sqrt[3]{2x} + 3\sqrt[3]{2x} = 6\sqrt[3]{2x}[/tex]