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Find the missing term of the following propotion.Show your solution

1.2:3=N : 6
2.1:N=5 : 10
3.8:10=4 : N
4.3:4=N : 12
5.N:15=2 : 3
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✏️PROPORTION

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Direction: Find the missing term of the following proportion. Show your solution.

Solution: To find the N, we simply equate the product of the means and the product of the extremes.

1. 2:3 = N:6

  • [tex] \underbrace{2 : \overbrace{ 3 = N }: 6}[/tex]

  • [tex]3⋅N = 2⋅6[/tex]

  • [tex]3N = 12[/tex]

  • [tex] \begin{gathered} \frac{ \cancel3N}{ \cancel3} = \frac{12}{3} \end{gathered}[/tex]

  • [tex]N = 4[/tex]

- Therefore, the missing term is:

  • [tex] \large \boxed{ \sf{ \green{ \: \: 4 \: \: }}}[/tex]

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2. 1:N = 5:10

  • [tex] \underbrace{1 : \overbrace{N = 5 }: 10}[/tex]

  • [tex]5⋅N = 1⋅10[/tex]

  • [tex]5N = 10[/tex]

  • [tex] \begin{gathered} \frac{ \cancel5N}{ \cancel5} = \frac{10}{5} \end{gathered}[/tex]

  • [tex]N = 2[/tex]

- Therefore, the missing term is:

  • [tex] \large \boxed{ \sf{ \green{ \: \: 2 \: \: }}}[/tex]

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3. 8:10 = 4:N

  • [tex] \underbrace{8 : \overbrace{10 = 4 }: N}[/tex]

  • [tex]10⋅4 = 8⋅N[/tex]

  • [tex]40= 8N[/tex]

  • [tex] \begin{gathered} \frac{40}{8} = \frac{ \cancel8N}{ \cancel8} \end{gathered}[/tex]

  • [tex]N = 5[/tex]

- Therefore, the missing term is:

  • [tex] \large \boxed{ \sf{ \green{ \: \: 5 \: \: }}}[/tex]

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4. 3:4 = N:12

  • [tex] \underbrace{3 : \overbrace{ 4 = N }: 12}[/tex]

  • [tex]4⋅N = 3⋅12[/tex]

  • [tex]4N = 36[/tex]

  • [tex] \begin{gathered} \frac{ \cancel4N}{ \cancel4} = \frac{36}{4} \end{gathered}[/tex]

  • [tex]N = 9[/tex]

- Therefore, the missing term is:

  • [tex] \large \boxed{ \sf{ \green{ \: \: 9 \: \: }}}[/tex]

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5. N:15 = 2:3

  • [tex] \underbrace{N : \overbrace{ 15 = 2 }:3}[/tex]

  • [tex]3⋅N = 15⋅2[/tex]

  • [tex]3N = 30[/tex]

  • [tex] \begin{gathered} \frac{ \cancel3N}{ \cancel3} = \frac{30}{3} \end{gathered}[/tex]

  • [tex]N = 10[/tex]

- Therefore, the missing term is:

  • [tex] \large \boxed{ \sf{ \green{ \: 10 \: }}}[/tex]

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