Sagot :
let x be the number of pigs
9-x be the number of cows
10-(9-x) or x+1 be the number of horses
x + 9 - x + x + 1 = 16
9 + x + 1 = 16
x + 10 = 16
x = 16 - 10
x = 6
9 - x = 3
x + 1 = 7
Therefore, there are 6 pigs, 3 cows and 7 horses
9-x be the number of cows
10-(9-x) or x+1 be the number of horses
x + 9 - x + x + 1 = 16
9 + x + 1 = 16
x + 10 = 16
x = 16 - 10
x = 6
9 - x = 3
x + 1 = 7
Therefore, there are 6 pigs, 3 cows and 7 horses