Answered

Read the given problem :
1.A color-blindness is a recessive,sex-linked disorder humans, A color-blind man has a child with a woman who is a carrier of the disorder.

Illustrate using a punnett square the probability of having children who will have normal vision and children who will be color-blind.

GUIDE QUESTIONS :
1.What is the genotype of the male ?
2.What is the genotype of the female ?
3.What is the chance that the child will be color-blind ?
4.What is the chance that a daughter will be color-blind?
5.What is the chance that a son will be color-blind ?


PLEASE HELP ME TO ANSWER THIS ..BECAUSE TOMORROW WILL BE THE DEADLINE OF OUR REPORTINGS.... PLEASE :(

Sagot :

AniMadelo13viz
Here are the answers :)
1) The genotype of the male is 50%[tex] X^{C} Y[/tex] , 50% [tex]XY[/tex]2)
2)female-50%  [tex] X^{C} X^{C} 50% X^{C} X[/tex] 
3) The chance that the child will be color blind is 50%
4) the chance the daughter will be color blind is 50% because the other one is just a carrier.
5) Same as number 4.