Step-by-step explanation:
(x-4)²-9=0;
x²-8x+16-9=0;
x²-8x+7=0;
a= 1, b= -8, c= 7;
[tex] x = \frac{ - b \frac{ + }{ } \sqrt { b {}^{2} - 4ac }}{2a} [/tex]
[tex]x = \frac{ - ( - 8) \frac{ + }{} \sqrt{ { - 8}^{2} } - 4(1)(7) }{2(1)} [/tex]
[tex]x = \frac{8 \frac{ + }{} \sqrt{64 - 28} }{2} [/tex]
[tex]x = \frac{8 \frac{ + }{} \sqrt{36} }{2} [/tex]
[tex]x = \frac{8 \frac{ + }{}6 }{2} [/tex]
X(sub1) = (8 + 6)/2
X(sub1) = 14/2 = 7
X(sub2) = (8-6)/2 = 2/2 = 1
therefore, the value of X are equals to 7 and 1.
