[tex]\tt{\huge{\blue{Explanation:}}}[/tex]
The force acting on an object is given by
[tex]\boxed{F = ma}[/tex]
where:
F = force
m = mass
a = acceleration
[tex]\tt{\huge{\red{Solution:}}}[/tex]
Solving for F
F = ma
F = (12.5 kg)(4.5 m/s²)
[tex]\boxed{F = \text{56.25 N}}[/tex]
Therefore, the net external force exerted on the watermelon is 56.25 N.
[tex]\\[/tex]
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