Answer:
[tex] {(x + 5)}^{2} = 3 \\ ( x + 5)(x + 5) = 3 \\ 2 {x}^{2} + 5x + 5x + 25 = 3 \\2 {x}^{2} + 10x + 25 = 3 \\ 2 {x}^{2} + 10x + 25 - 3 = 3 - 3 \\ 2 {x}^{2} + 10x + 22 = 0 \\ a = 2 \: b = 10 \: c \: = 22 \\ [/tex]
[tex]3 {(x + 5)}^{2} - 5 = 0 \\ (3)( {2x}^{2} + 10x + 25) - 5 = 0 \\ {6x}^{2} + 30x + 75 - 5 = 0 \\ {6x}^{2} + 30x + 70 = 0 \\ a = 6 \: b = 30 \: c = 70[/tex]
check mo na lang po kung tama and correct me if i'm worng
