Question:
Four angle measure in a convex pentagon re given .Find the measure of the fifth angle.
70,80,92,120
Answer:
Sum of interior angles of Pentagon = 540°
let
∠5 = measure of the fifth interior angle
solve for ∠5,
∠1 + ∠2 + ∠3 + ∠4 + ∠5 = 540°
70° + 80° + 92° + 120° + ∠5 = 540°
362° + ∠5 = 540°
∠5 = 540° - 362°
∠5 = 178°
[tex]\therefore \;\large\boxed{\text{\sf The fifth interior angle is $\sf 178^\circ$}}[/tex]
* as always, double check my answers for errors or carelessness.
#No to copy paste solution
#No to plagiarism
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