1. A sample of helium has a volume of 521dm³ at a pressure of 75 cm Hg and a temperature of 18°C. When the temperature is increases to 23°C, what is the volume of the helium?

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Sagot :

Answer:

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Explanation:

V1T1=V2T2

V1 = 521 dm³; T1 = (18 + 273.15) K = 291 K

V2 = ?; T2 = (23 + 273.15) K = 296 K

V2=V1×T2T1 = 521 dm³ ×296 K291 K = 530. dm³

This makes sense. The absolute temperature increased by a factor of about 2 %, so the volume increased by about 2 % (10 dm³).