Tdyahooviz
Answered

solving quadratic equatons by extracting square roots
(x-3)^2=12

Sagot :

Cythereaviz
x= square root of 12 minus 3 or x= 2 square root of 3 minus 3
Ken21viz
[tex] x-3^{2} [/tex]=12
[tex] \sqrt{[tex] x-3^{2} [/tex]} [/tex]=[tex] \sqrt{12} [/tex]
(x-3)=-/+3.46410161514
x-3+3=+3.46410161514+3
x=6.46410161514

x-3=-3.46410161514+3
x=-0.46410161514

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