Selinaviz
Answered

Please solve this:

log49 [tex] \sqrt{7} [/tex] = [tex] \frac{1}{2} [/tex]x
log4[tex] \sqrt[3]{16} [/tex] =

Sagot :

Bituinviz
[tex]\\log_{49}\sqrt7=\frac12x\iff 49^{\frac12x}=\sqrt7 \\ \\7^x=7^{\frac12} \\ \\x=\frac12 \\ \\log_4\sqrt[3]16=log_44^{\frac23}=\frac23[/tex]