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Pahelp po ako sa math. refer to the circle to answer the questions

If AE = 41, what must be the length of cord EF so that the perimeter of ∆EFS is 50?


If CF=50, what must be the length of chord AC so that the perimeter of ∆ACS is 60?​

Pahelp Po Ako Sa Math Refer To The Circle To Answer The QuestionsIf AE 41 What Must Be The Length Of Cord EF So That The Perimeter Of EFS Is 50 If CF50 What Mus class=

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Problem:

If AE = 41, what must be the length of cord EF so that the perimeter of ∆EFS is 50?

Solution:

AE = 41

ES = AE/2

ES = 41/2

ES = 20.5

ES = AS = FS = CS = 20.5

∆EFS = 50

∆EFS = ES + FS + EF

50 = 20.5 + 20.5 + EF

EF = 50 - 20.5 - 20.5

EF = 9

Answer:

Chord EF = 9

Problem:

If CF = 50, what must be the length of chord AC so that the perimeter of ∆ACS is 60?

Solution:

CF = 50

CS = CF/2

CS = 50/2

CS = 25

CS = FS = ES = AS = 25

∆ACS = 60

∆ACS = CS + AS + AC

60 = 25 + 25 + AC

AC = 60 - 25 - 25

AC = 10

Answer:

Chord AC = 10

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