You are tasked to create a 7-digit password from the numbers 0,3,6,8,2,1,9, and 4

if no repetition of digits is allowed how many possible passwords will you create?​


Sagot :

[tex] \large\underline \bold{{SOLUTION}}[/tex]

[tex]\textrm{If repetition is not allowed}[/tex]

We can plug 7 numbers on the first digit: because zero is not included

  • 7

7 again on the second because zero can be included.

  • 7 7

6 for the third because repetition is not allowed

  • 7 7 6

5 for the fourth because repetion is not allowed

  • 7 7 6 5

4 for the fourth because repetion is not allowed

  • 7 7 6 5 4

3 for the fourth because repetion is not allowed

  • 7 7 6 5 4 3

2 for the fourth because repetion is not allowed

  • 7 7 6 5 4 3 2

By fundamental counting principle: We will multiply all of the entries:

  • 7×7×6×5×4×3×2 = 35,280 ways

[tex] \large\underline{ \bold{ANSWER}}[/tex]

[tex]\longmapsto\boxed{\textrm{P=35280 ways}}[/tex]