What is the standard deviation of the following numbers if treated as data from a sample? 12, 11, 14, 10, 8, 13, 11, 9, 10 *
1 point


Sagot :

Answer:

1.900292375

Step-by-step explanation:

First, find the mean.

12 + 11 + 14 + 10 + 8 + 13 + 11 + 9 + 10 = 98

98/9 = 10.88888889

Second, minus every number with the mean.

12 - 10.88888889 = 1.11111111

11 - 10.88888889 = 0.11111111

14 - 10.88888889 = 3.111111111

10 - 10.88888889 = -0.8888888889

8 - 10.88888889 = -2.888888889

13 - 10.88888889 = 2.111111111

11 - 10.88888889 = 0.11111111

9 - 10.88888889 = -1.888888889

10 - 10.88888889 = -0.8888888889

Third, square all the differences.

(1.11111111)² = 1.234567901

(0.11111111)² = 0.01234567901

(3.111111111)² = 9.679012345

(-0.8888888889)² = 0.7901234568

(2.888888889)² = 8.345679013

(2.111111111)² = 4.456790123

(0.11111111)² = 0.01234567901

(1.888888889)² = 3.567901235

(-0.8888888889)² = 0.7901234568

Fourth, calculate the variance.

To calculate the variance, add all of the squared differences.

1.234567901 + 0.01234567901 + 9.679012345 + 0.7901234568 + 8.345679013 + 4.456790123+0.01234567901 + 3.567901235 + 0.7901234568 = 28.88888889

Next is divide the sum of squared differences to 9(count of the numbers) - 1

28.88888889/8 = 3.611111111

Lastly, take the root of the variance.

[tex] \sqrt{3.611111111} [/tex]

= 1.900292375