how to solve this (2b+1)(3b-2)=55

Sagot :

Use FOIL method... ( First Outer Inner Last )

Solution:
                             (2b+1) (3b-2) = 55
First, 2b x 3b = 6b²
Outer, 2b (-2) = -4b
Inner, 1 x 3b = 3b
Last, 1 (-2) = -2

6b²-4b+3b-2

Then add the two numbers between them ( the -4b and the 3b )

-4b+3b = -12b

And...

6b²-12b-2 = 55 - 55

Final answer is;

6b²-12b-2 = 0