EngrBenamerviz
Answered

y=x^{3}-3x^{2}+4x-12
find the first derivatives

Sagot :

Riza1viz
[tex]y=x^{3}-3x^{2}+4x-12 \\a'=0\\(ax^n)'=a\cdot n \cdot x ^{n-1} \\\\(x^{3})'=3x^{3-1}=3x^2\\ (-3x^2)'=-3\cdot 2\cdot x^{2-1} = -6x \\(4x)'=4\cdot 1\cdot x^{1-1}=4\cdot x^0=4\cdot 1=4\\(-12)'=0\\\\y'=3x^2-6x+4[/tex]