Formula for distance:
[tex]d = \sqrt{ (x_{2} -x_{1)}) ^{2} + (y_{2} -y_{1)}) ^{2}[/tex]
Given:
x2 = 8
x1 = -3
y2 = -4
y1 = -4
Solution:
[tex]d = \sqrt{ (x_{2} -x_{1)}) ^{2} + (y_{2} -y_{1)}) ^{2}}\\d = \sqrt{(8-(-3)^{2} + (-4 - (-4)^{2}) } \\d = \sqrt{121+0} \\d = \sqrt{121}[/tex]
Answer:
11 units
