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The volume of a cubical box is 64 cm3

. If the length of the side is reduced by x cm,

what is the new volume of the new cubical box?

Sagot :

Answer:

64 - 48x + 12x² - x³ cm³

Step-by-step explanation:

Let the side be s.

s³ = 64

s = ∛64 = 4

If 4 is reduced by x cm, then the new area is:

(4 - x)³

Apply the formula (a - b)³ = a³ - 3a²b + 3ab² - b³

So,

(4 - x)³ = 4³ - 3(4²)x + 3(4)(x²) - x³

(4 - x)³ = 64 - 48x + 12x² - x³

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