Monblakeviz
Answered

Solve the triangle ABC, given a=31.5 inches, b=51.8 inches and A=33'' 40'.

Sagot :

BookerNotDewittviz
Law of sines

sinB = bsinA/ a
sinB = (51.8)sin(33'40'')/ (31.5)
B = 65 (degrees) 43'46''

C= 180 - (A+B)
C= 180- [33'40'' + 65(degrees)43'46'']
C= 80(degrees)36'14''

c= asinC/sinA
c= (31.5)sin[80(degrees)36'14'']/ sin(33'40'')
c= 56.05

Sorry if it's late