Answer:
Khatri
Answered 2 years ago
here in the above fig o is the radius MN and PQ are the chords where
MN = 6 cm
PQ= 8 cm
radius ON=OQ=5 cm.
in a traingle OAN
AN =6/2 =3 cm [the perpendicular drawn from the center to the chord bisects the chords.]
now using pythogorean theorem
ON^2= OA^2 +AN^2
5*5= OA^2 +3*3
OA= 4 cm.
similarly in traingle OBQ
OQ=4 cm.
from the similar process above
OB= 3 cm
NOW the distance between them is AB= AO+OB = 4+3 = 7cm.
