This is the formula for the sum of an arithmetic series [tex] \frac{n}{2} [2 a_{1} +(n-1)d][/tex] (d is for the difference and n is for the number of terms) We substitute the values [tex] \frac{n}{2} [50+(n-1)2] = 880 [/tex] [tex] \frac{n}{2} [50+2n-2] [/tex] [tex] \frac{n}{2} [48+2n][/tex]