Yssangviz
Answered

Find the 1st to 14 term of the arithmetic series 2+5+8+11+14+17...

Sagot :

let:
a1= 2
d=3   (5-2)
n= 14

S=n/2[2a1+(n-1)d]
S=14/2[2(2)+(14-1)3]
S=14/2[4+(13)3]
S=14/2[4+39]
S=7[43]
S=301