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what is x in (8/27)^2x+1=4/9 i need complete solution

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Riza1viz
[tex](\frac{8}{27} )^{2x+1}=\frac{4}{9} \\\\((\frac{2}{3})^3 )^{2x+1}=(\frac{2}{3})^2\\\\ (\frac{2}{3} )^{3(2x+1)}=(\frac{2}{3})^2 \\\\ (\frac{2}{3} )^{6x+3}=(\frac{2}{3})^2\\\\6x+3=2\\\\6x=2-3\\\\6x=-1\ \ / :6\\\\x=-\frac{1}{6} [/tex]