Mariferemultaviz
Answered

a wire, whose lenght is at most 62 cm is bent to form a rectangle. if the lenght of the rectangle is 7 cm longer than the widht, what is the maximum area of the rectangle?

Sagot :

Manelviz
Let ..
P = perimeter = 62
L= length = x+7
W = width = x

Solution:
  Since, the formula in getting the perimeter of rectangle is 2L+2W, therefore,
 P= 2(x+7) + 2(x)
 62 = 2x+7x+2x
 62 = 11x
 x= 5.6

L= 5.6+7
 L= 12.6

 To get the area, use the formula A=lw
 A= (12.6) (5.6)
A= 70.56 [tex] cm^{2} [/tex]

 The area of the rectangle is [tex] 70.56 cm^{2} [/tex].