We have not tackled more of this, but I think this is how to answer it:
Given: 150 tons = total solution of metal and ore
8 - 1/2 % = percentage of metal contained in the solution
Asked: How much metal will be obtained by the solution.
Solution:
Percentage by mass solute = mass solute / mass solution x 100
8% (maximum) = x / 150 tons x 100
8% / 100 = x / 150 tons x 100 / 100
0. 08 = x /150
0. 08 (150 tons) = x/ 150 tons (150 tons)
12 tons = x = mass solute = mass solute = maximum mass of metal found
in the solution,
1/2 % or 0.5 % ( minimum) = x / 150 tons x 100
0. 5 % / 100 = x /150 tons x 100 / 100
0. 005 = x / 150 tons
0. 005 x 150 tons = x/ 150 tons (150 tons)
0. 75 tons = x
Therefore, there are 12 tons - 0.75 tons of metal found on the ore if I am not mistaken.
(somebody correct me if I am wrong)
