find the equation of the line through (2,4) and (4,6)

Sagot :

(y-y1)=((y2-y1)/(x2-x1)) (x-x1)

(y-4)=((6-4)/(4-2)) (x-2)

y-4= (1)(x-2)

y=x+2
[tex] ( 2,4), \ \ \ (4,6) \\ \\ First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 4-2}{6-4} = \frac{2}{2}=1 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1})\\\\y-4=1(x-2)\\\\y-4=x-2\\\\x-2-y+4=0\\\\ x-y+2=0 [/tex]