[tex]Let's\ use\ trial\ and\ error\ where\ you\ are\ free\ to\ give\ the \\ value\ of\ either\ x\ and\ y. \\ \\ Here's\ my\ solution\ in\ which\ I\ substitute\ x\to5. \\ \\ Solving\ for\ the\ value\ of\ y\ in\ which\ x=5 \\ \\ Solution; \\ 4y=4x+16 \\ \\ 4y=4(5)+16 \\ \\ 4y=20+16 \\ \\ \frac{4y}{4}=\frac{36}{4} \\ \\ \boxed{\boxed{y=9}} \\ \\ \\ Checking; \\ 4y=4x+16 \\ \\ 4(9)=4(5)+16 \\ \\ 36=20+16 \\ \\ \boxed{36=36}\ \underline{TRUE} \\ \\ Hope\ it\ Helps:) \\ Domini [/tex]
