Mmvviz
Answered

How can we prove this Trigonometric identity???

secФ = [tex] \\ \frac{sinФ}{cotФ \frac} [/tex] + cosФ

Sagot :

secФ=[tex] \frac{sin ^{2} }{cos} [/tex]+cos
secФ=[tex] \frac{sin ^{2}+cos ^{2} }{cos} [/tex]
secФ=[tex] \frac{1}{cos} [/tex]
secФ=secФ

I hope na gets mo yan,pythagorian at reciprocal identity yan